Power output of motor = (motor efficiency) × (power input) power output of motor = 0.96 × 44 kw power output of motor = 42.24 kw now, we need to find the power required to pump the oil. The inlet and outlet diameters of the piper are 8 cm and 12 cm, respectively. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Web an oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m 3 at a rate of 0.1 m 3 /s. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.
Web an oil pump is drawing 44 kw of electric power while pumping oil with \rho ρ = 860 kg/m^3 at a rate of 0.1 m^3/s. Electric work in $w_{in} = 44 kw$ density $\rho =860 \dfrac{kg}{m^3}$ inner diameter of the pipe $d_{in}= 8cm = 0.08 m$ outer diameter of the pipe $d_{out}= 12cm = 0.12m$ pump’s volume flow rate $v = 0.1. An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m3 at a rate of 0.1 m3 /s. An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg / m 3 at a rate of 0.1 m 3 / s.
An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg / m 3 at a rate of 0.1 m 3 / s. P electric = 44 × 10 3 w the motor efficiency (η motor) is given as 90 percent. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.
A pump motor system is what we have here, and we can either look at it as the motor and then the pump, or we can also look at it as a whole system. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Pressure rise, p = 500kpa. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.
An oil pump is drawing 44 kw of electric power while pumping oil with ï =860 kg/mâ³ at a rate of 0.1 mâ³/s. Web an oil pump is drawing 44 kw of electric power while pumping oil with p= 860 kg/m3 at a rate of 0.1 m3/s. Web mechanical engineering questions and answers.
If The Pressure Rise Of Oil In The Pump Is Measured To Be 500 Kpa And The Motor Efficiency Is 90 Percent, Determine The Mechanical Efficiency Of The Pump.
Input power, p = 44 kw. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Given that the motor efficiency is 90%, we can calculate the power output: Density of oil, ρ = 860 kg/m³.
Web An Oil Pump Is Drawing 44 Kw Of Electric Power While Pumping Oil With P = 860 Kg/M^3 At A Rate Of 0.1 M^3/S.
Power output of motor = (motor efficiency) × (power input) power output of motor = 0.96 × 44 kw power output of motor = 42.24 kw now, we need to find the power required to pump the oil. We have given that an oil pump is drawing 44 kw of electric power. Web an oil pump is drawing 44 kw of electric power while pumping oil with r = 860 kg/m3 at a rate of 0.1 m3/s. Electric work in $w_{in} = 44 kw$ density $\rho =860 \dfrac{kg}{m^3}$ inner diameter of the pipe $d_{in}= 8cm = 0.08 m$ outer diameter of the pipe $d_{out}= 12cm = 0.12m$ pump’s volume flow rate $v = 0.1.
Inlet Diameter = 8 Cm And Outlet Diameter = 12Cm.
If the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 91 percent, determine the mechanical efficiency of the pump. Motor efficiency, η = 90 % inlet diameter, d₁ = 8 cm. An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg / m 3 at a rate of 0.1 m 3 / s. P electric = 44 × 10 3 w the motor efficiency (η motor) is given as 90 percent.
Web Mechanical Engineering Questions And Answers.
Web if the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m3 at a rate of 0.1 m3 /s. The mechanical efficiency of the pump is 91.8 % explanation: The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.
Web for the shaft power of the pump we have the following equation: Web the power output of the pump can be calculated using the formula: Power output of motor = (motor efficiency) × (power input) power output of motor = 0.96 × 44 kw power output of motor = 42.24 kw now, we need to find the power required to pump the oil. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Web an oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m 3 at a rate of 0.1 m 3 /s.