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For algebraic surfaces this result follows from the hodge index theorem. If \ (y\) has a multiplicative inverse, then division by \ (y\) is easy: Using this, we construct a stable theory. If the picard number is bigger than 1, then the intersection pairing on the orthogonal.
Pdf | Let X Be A Smooth Complete Algebraic Variety.
Modified 8 years, 1 month ago. Web is the pullback of an ample divisor always nef? Let f:x→y be a morphism from x to another algebraic variety y, which is neither. Web 11.5k 2 41 74.
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Now The Result Follows Directly.
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